WebApr 9, 2024 · 2 Answers Sahar Mulla Apr 9, 2024 y = 3sin(x) −sin(3x) y' = 3cosx −[cos(3x) ⋅ 3] t [applying chain rule tosin(3x)] y' = 3(cosx − cos3x) Answer link Jim G. Apr 9, 2024 dy dx = 3cosx −3cos3x Explanation: differentiate sin3x using the chain rule Given y = f (g(x)) then dy dx = f '(g(x)) × g'(x) ← chain rule y = 3sinx − sin3x WebUsing the chain rule the differential of 3 (sinx)^2 is: The differential of 3u^2 multiplied by the differential of u which in this case = sinx So that would be 6u * cosx And since u = sinx that makes it 6sinxcosx Thanks this makes sense _princessxox why are you doing this at AS it's C3 It's just a bit of cheeky self teach uno Reply 6 5 years ago
Find the Derivative - d/dx y=3sin(2x) Mathway
WebBecause f(-2) = -14 at x = -2, and because f(x) and h(x) are inverse functions, h( f(x) ) = x. This means that h(-14) = -2 Because h( f(-2) ) = -2. ... Plus the derivative of three X with respect to X which that's just going to be three. And you could do that, it's just the power rule. But this was X to the first power, one times three, X to ... WebMar 30, 2024 · Ex 5.7, 11 If y=5 cos〖𝑥−3 sin𝑥 〗 ,prove that 𝑑2𝑦/𝑑𝑥2 + y = 0 y = 5 cos〖𝑥−3 sin𝑥 〗 Differentiating 𝑤.𝑟.𝑡.𝑥 𝑑𝑦/𝑑𝑥 = (𝑑(5 cos〖𝑥−3 sin𝑥 〗))/𝑑𝑥 𝑑𝑦/𝑑𝑥 = (𝑑(5 cos𝑥))/𝑑𝑥 − (𝑑(3 sin𝑥))/𝑑𝑥 𝑑𝑦/𝑑𝑥 = − 5 sin𝑥 − 3 cos𝑥 Again ... how do i log into followmyhealth
Calculus problems - Find the derivative of the function f(x) = x^2 ...
WebSep 7, 2024 · The derivative of the sine function is the cosine and the derivative of the cosine function is the negative sine. d dx(sinx) = cosx d dx(cosx) = − sinx Proof Because the proofs for d dx(sinx) = cosx and d dx(cosx) = − sinx use similar techniques, we provide only the proof for d dx(sinx) = cosx. WebApr 8, 2024 · Explanation: differentiate sin3x using the chain rule. Given y = f (g(x)) then. dy dx = f '(g(x)) × g'(x) ← chain rule. y = 3sinx − sin3x. ⇒ dy dx = 3cosx − cos3x × d dx (3x) … WebFree Online Derivative Calculator allows you to solve first order and higher order derivatives, providing information you need to understand derivative concepts. … how much lumbrokinase to take daily